Free Printable WorksheetMathCalculus IIMath CurriculumAP Calculus BC Unit 10; CCSS.HSA.SSE, HSF.BF; CCSS.MP2, MP5, MP6, MP7, MP8; Integrated Calculus II Standards CAL2-PS; TEKS 19 TAC section 111.55

CAL2.149 Taylor Series from Known Series Worksheet

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Worksheet Overview & Skills Covered

Core academic competencies and curriculum alignment

This Calculus II Math worksheet provides structured practice on CAL2.149 Taylor Series from Known Series. Students are guided through targeted exercises that build foundational understanding, computational accuracy, and critical thinking skills.

CAL2.149 Taylor Series from Known Series - Select the correct transformed series using substitution, multiplication, differentiation, or integration. Standards: AP Calculus BC Unit 10; CCSS.HSA.SSE, HSF.BF; CCSS.MP2, MP5, MP6, MP7, MP8; Integrated Calculus II Standards CAL2-PS; TEKS 19 TAC section 111.55

Whether you are an educator preparing classroom handouts, a tutor reinforcing weekly topics, or a parent supporting homeschool learning, this printable resource gives students the deliberate practice required to achieve subject fluency and master state standards.

Grade

Calculus II

Subject

Math

Domain

Math Curriculum

Formats

PDF & DOCX

Sample Practice Problems

Preview the types of problems and questions covered in this worksheet

Below are sample questions representative of the exercises included on this worksheet and related CAL2.149 Taylor Series from Known Series skill assessments:

Problem 1Difficulty: Mastery
Use the sine series to select the Maclaurin series for \(\int_0x\frac{\sin(t2)}{t}\,dt\).
A\(\sum_{n=0}\infty(-1)n\frac{x4n+1}{(4n+1)(2n+1)!}\)
B\(\sum_{n=0}\infty(-1)n\frac{x4n+2}{(2n+1)!}\)
C\(\sum_{n=0}\infty(-1)n\frac{x2n+2}{(2n+2)(2n+1)!}\)
D\(\sum_{n=0}\infty(-1)n\frac{x4n+2}{(4n+2)(2n+1)!}\)
Solution & Explanation:Because \(\sin(t2)=\sum(-1)n t4n+2/(2n+1)!\), dividing by \(t\) gives \(t4n+1\), and integrating gives the factor \(4n+2\).
Problem 2Difficulty: Mastery
Select the Taylor series centered at \(x=2\) for \(\cos(2x-4)\).
A\(\sum_{n=0}\infty(-1)n\frac{2n(x-2)2n}{(2n)!}\)
B\(\sum_{n=0}\infty(-1)n\frac{(x-2)2n}{(2n)!}\)
C\(\sum_{n=0}\infty(-1)n\frac{22n(x-2)2n}{(2n)!}\)
D\(\sum_{n=0}\infty(-1)n\frac{22n(x-2)2n+1}{(2n+1)!}\)
Solution & Explanation:Since \(2x-4=2(x-2)\), substitute \(u=2(x-2)\) into the cosine series. The even power produces \(22n(x-2)2n\).
Problem 3Difficulty: Mastery
Select the Taylor series centered at \(x=1\) for \(e-(x-1)^2\).
A\(\sum_{n=0}\infty\frac{(x-1)2n}{n!}\)
B\(\sum_{n=0}\infty(-1)n\frac{(x-1)2n}{n!}\)
C\(\sum_{n=0}\infty(-1)n\frac{(x-1)n}{n!}\)
D\(e-1\sum_{n=0}\infty(-1)n\frac{(x-1)2n}{n!}\)
Solution & Explanation:This is \(eu\) with \(u=-(x-1)2\). Thus \(un=(-1)n(x-1)2n\), and no extra constant factor appears.

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QWhat grade level and standards does this worksheet align with?

This worksheet is designed specifically for Calculus II Math students. It aligns with educational standard AP Calculus BC Unit 10; CCSS.HSA.SSE, HSF.BF; CCSS.MP2, MP5, MP6, MP7, MP8; Integrated Calculus II Standards CAL2-PS; TEKS 19 TAC section 111.55 (Select the correct transformed series using substitution, multiplication, differentiation, or integration. Standards: AP Calculus BC Unit 10; CCSS.HSA.SSE, HSF.BF; CCSS.MP2, MP5, MP6, MP7, MP8; Integrated Calculus II Standards CAL2-PS; TEKS 19 TAC section 111.55).

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