Free Printable WorksheetMathCalculus IIMath CurriculumAP Calculus BC Unit 8; FL MA.912.C.5.5-C.5.7; CCSS.HSM; CCSS.HSN.Q.1-3; CCSS.MP2, MP4, MP6, MP7; Integrated Calculus II Standards CAL2-APP; TEKS 19 TAC section 111.55

CAL2.66 Washer Method Around a Coordinate Axis Worksheet

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Worksheet Overview & Skills Covered

Core academic competencies and curriculum alignment

This Calculus II Math worksheet provides structured practice on CAL2.66 Washer Method Around a Coordinate Axis. Students are guided through targeted exercises that build foundational understanding, computational accuracy, and critical thinking skills.

CAL2.66 Washer Method Around a Coordinate Axis - Select the correct washer-method radii and integral for a region revolved around an axis. Standards: AP Calculus BC Unit 8; FL MA.912.C.5.5-C.5.7; CCSS.HSM; CCSS.HSN.Q.1-3; CCSS.MP2, MP4, MP6, MP7; Integrated Calculus II Standards CAL2-APP; TEKS 19 TAC section 111.55

Whether you are an educator preparing classroom handouts, a tutor reinforcing weekly topics, or a parent supporting homeschool learning, this printable resource gives students the deliberate practice required to achieve subject fluency and master state standards.

Grade

Calculus II

Subject

Math

Domain

Math Curriculum

Formats

PDF & DOCX

Sample Practice Problems

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Below are sample questions representative of the exercises included on this worksheet and related CAL2.66 Washer Method Around a Coordinate Axis skill assessments:

Problem 1Difficulty: Mastery
The region between x=y and x=2-y for 0<=y<=2 is revolved around the y-axis. Which washer-method setup is correct?
AR=2-y, r=y for all 0<=y<=2; V=π∫_{0}2[(2-y)2-y2] dy
BR=y, r=2-y for all 0<=y<=2; V=π∫_{0}2[y2-(2-y)2] dy
CR=2-y, r=y for all 0<=y<=2; V=π∫_{0}2[(2-y)-y]2 dy
DR=2-y, r=y on [0,1]; R=y, r=2-y on [1,2]; V=π∫_{0}1[(2-y)2-y2] dy+π∫_{1}2[y2-(2-y)2] dy
Solution & Explanation:Horizontal distances from the y-axis switch at y=1. On [0,1], x=2-y is the outer radius; on [1,2], x=y is the outer radius. Splitting keeps every washer area nonnegative.
Problem 2Difficulty: Mastery
The region between y=x and y=2-x for 0<=x<=2 is revolved around the x-axis. Which washer-method setup is correct?
AR=2-x, r=x for all 0<=x<=2; V=π∫_{0}2[(2-x)2-x2] dx
BR=x, r=2-x for all 0<=x<=2; V=π∫_{0}2[x2-(2-x)2] dx
CR=2-x, r=x on [0,1]; R=x, r=2-x on [1,2]; V=π∫_{0}1[(2-x)2-x2] dx+π∫_{1}2[x2-(2-x)2] dx
DR=2-x, r=x for all 0<=x<=2; V=π∫_{0}2[(2-x)-x]2 dx
Solution & Explanation:Both line segments are above the x-axis, but the farther distance changes at x=1. Use R=2-x on [0,1] and R=x on [1,2]. An unsplit integral would produce negative washer area on part of the interval.
Problem 3Difficulty: Mastery
The region between x=2+sin(y) and x=2+cos(y) for 0<=y<=π/2 is revolved around the y-axis. Which washer integral is correct?
AR=2+cos(y), r=2+sin(y) for all 0<=y<=π/2; V=π∫_{0}π/2[(2+cos(y))2-(2+sin(y))2] dy
BR=2+cos(y), r=2+sin(y) on [0,π/4]; R=2+sin(y), r=2+cos(y) on [π/4,π/2]; V=π∫_{0}π/4[(2+cos(y))2-(2+sin(y))2] dy+π∫_{π/4}π/2[(2+sin(y))2-(2+cos(y))2] dy
CR=2+sin(y), r=2+cos(y) for all 0<=y<=π/2; V=π∫_{0}π/2[(2+sin(y))2-(2+cos(y))2] dy
DR=cos(y), r=sin(y); V=π∫_{0}π/2[(cos(y))2-(sin(y))2] dy
Solution & Explanation:For y-axis washers, compare horizontal distances from the y-axis. The distances 2+sin(y) and 2+cos(y) switch order at y=π/4, so the integral must split there.

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QWhat grade level and standards does this worksheet align with?

This worksheet is designed specifically for Calculus II Math students. It aligns with educational standard AP Calculus BC Unit 8; FL MA.912.C.5.5-C.5.7; CCSS.HSM; CCSS.HSN.Q.1-3; CCSS.MP2, MP4, MP6, MP7; Integrated Calculus II Standards CAL2-APP; TEKS 19 TAC section 111.55 (Select the correct washer-method radii and integral for a region revolved around an axis. Standards: AP Calculus BC Unit 8; FL MA.912.C.5.5-C.5.7; CCSS.HSM; CCSS.HSN.Q.1-3; CCSS.MP2, MP4, MP6, MP7; Integrated Calculus II Standards CAL2-APP; TEKS 19 TAC section 111.55).

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