Free Printable WorksheetScienceGrade 11Science CurriculumNGSS HS-PS1-4; AP Chem Units 6 and 9; CCSS HSN-Q.A.1-3 and HSA-CED.A.1-4

11.78 Specific Heat and Calorimetry Worksheet

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Worksheet Overview & Skills Covered

Core academic competencies and curriculum alignment

This Chemistry Science worksheet provides structured practice on 11.78 Specific Heat and Calorimetry. Students are guided through targeted exercises that build foundational understanding, computational accuracy, and critical thinking skills.

Specific Heat and Calorimetry: Calculate heat transfer using q = mcDeltaT, calorimeter data, specific heat, mass, and temperature change. Aligned to NGSS, CCSS, AP Chemistry/Pre-AP Chemistry, and representative state chemistry framework crosswalks NGSS HS-PS1-4; AP Chem Units 6 and 9; CCSS HSN-Q.A.1-3 and HSA-CED.A.1-4 - Specific Heat and Calorimetry Chemistry Standards Crosswalk: National: NGSS HS-PS1-4; AP Chem Units 6 and 9; CCSS HSN-Q.A.1-3 and HSA-CED.A.1-4. State frameworks: TX TEKS 112.43(c)(13); FL SC.912.P.10.4, P.10.6; MA/CA/NY/NJ HS-PS1 energy standards; GA and VA thermochemistry/energy standards.

Whether you are an educator preparing classroom handouts, a tutor reinforcing weekly topics, or a parent supporting homeschool learning, this printable resource gives students the deliberate practice required to achieve subject fluency and master state standards.

Grade

Chemistry

Subject

Science

Domain

Science Curriculum

Formats

PDF & DOCX

Sample Practice Problems

Preview the types of problems and questions covered in this worksheet

Below are sample questions representative of the exercises included on this worksheet and related 11.78 Specific Heat and Calorimetry skill assessments:

Problem 1Difficulty: Mastery

A 100.0 g hot metal sample at 95.0°C is placed into 150.0 g water at 22.0°C in a calorimeter with Ccal = 40.0 J/°C. The final temperature is 26.5°C. What is the metal's specific heat?

A0.412 J/(g°C)

B0.876 J/(g°C)

C0.385 J/(g°C)

D0.438 J/(g°C)

Solution & Explanation:Water absorbs 150.0(4.18)(4.5) = 2821.5 J and the calorimeter absorbs 40.0(4.5) = 180 J. Total heat gained is 3001.5 J. The metal cools by 68.5°C, so c = 3001.5 / [(100.0)(68.5)] = 0.438 J/(g°C).

Problem 2Difficulty: Mastery

Water and aluminum each need to absorb 5.00 kJ while warming by 10.0°C. Use cwater = 4.18 J/(g°C) and cAl = 0.900 J/(g°C). Which comparison is correct?

AMore water mass is needed than aluminum mass.

BEqual masses are needed because q is the same.

CMore aluminum mass is needed than water mass.

DNo aluminum can absorb heat without melting.

Solution & Explanation:Required mass is q/(c Delta T). Water needs about 120 g, while aluminum needs about 556 g because aluminum has a smaller specific heat.

Problem 3Difficulty: Mastery

A 250. g coolant sample with c = 3.60 J/(g°C) drops in temperature by 12.0°C as it absorbs heat from a device and then releases heat to a radiator. What is q for the coolant during the cooling step?

A+10.8 kJ

B-10.8 kJ

C-7.50 kJ

D+1.08 kJ

Solution & Explanation:During the cooling step, Delta T = -12.0°C. q = (250.)(3.60)(-12.0) = -10800 J = -10.8 kJ.

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Frequently Asked Questions

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QWhat grade level and standards does this worksheet align with?

This worksheet is designed specifically for Chemistry Science students. It aligns with educational standard NGSS HS-PS1-4; AP Chem Units 6 and 9; CCSS HSN-Q.A.1-3 and HSA-CED.A.1-4 (National: NGSS HS-PS1-4; AP Chem Units 6 and 9; CCSS HSN-Q.A.1-3 and HSA-CED.A.1-4. State frameworks: TX TEKS 112.43(c)(13); FL SC.912.P.10.4, P.10.6; MA/CA/NY/NJ HS-PS1 energy standards; GA and VA thermochemistry/energy standards.).