Free Printable WorksheetScienceGrade 11Science CurriculumNGSS HS-PS1-5; AP Chem Unit 5; CCSS HSS-ID and HSA-CED.A

11.90 Integrated Rate Laws Worksheet

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Worksheet Overview & Skills Covered

Core academic competencies and curriculum alignment

This Chemistry Science worksheet provides structured practice on 11.90 Integrated Rate Laws. Students are guided through targeted exercises that build foundational understanding, computational accuracy, and critical thinking skills.

Integrated Rate Laws: Use zero-, first-, and second-order integrated rate laws to relate concentration and time. Aligned to NGSS, CCSS, AP Chemistry/Pre-AP Chemistry, and representative state chemistry framework crosswalks NGSS HS-PS1-5; AP Chem Unit 5; CCSS HSS-ID and HSA-CED.A - Integrated Rate Laws Chemistry Standards Crosswalk: National: NGSS HS-PS1-5; AP Chem Unit 5; CCSS HSS-ID and HSA-CED.A. State frameworks: TX TEKS reaction-rate expectations; FL SC.912.P.8.8 connections; CA/NY/NJ HS-PS1-5; MA chemistry reaction-rate standards; GA/VA kinetics standards.

Whether you are an educator preparing classroom handouts, a tutor reinforcing weekly topics, or a parent supporting homeschool learning, this printable resource gives students the deliberate practice required to achieve subject fluency and master state standards.

Grade

Chemistry

Subject

Science

Domain

Science Curriculum

Formats

PDF & DOCX

Sample Practice Problems

Preview the types of problems and questions covered in this worksheet

Below are sample questions representative of the exercises included on this worksheet and related 11.90 Integrated Rate Laws skill assessments:

Problem 1Difficulty: Mastery

Use the accompanying second-order graph equation. Which pair of predictions is correct?

A[A] at 15.0 min is 0.200 M, and [A] reaches 0.100 M at 10.0 min.

B[A] at 15.0 min is 0.0800 M, and [A] reaches 0.100 M at 25.0 min.

C[A] at 15.0 min is 0.500 M, and [A] reaches 0.100 M at 20.0 min.

D[A] at 15.0 min is 0.125 M, and [A] reaches 0.100 M at 20.0 min.

Solution & Explanation:From 1/[A] = 2.00 + 0.400t, at 15.0 min, 1/[A] = 8.00, so [A] = 0.125 M. For [A] = 0.100 M, 10.0 = 2.00 + 0.400t, so t = 20.0 min.

Problem 2Difficulty: Mastery

For a first-order reaction, [A]_0 = 0.800 M, [A]_t = 0.200 M, and k = 0.0693 min^-1. A student uses log base 10 instead of natural log. What is the correct time?

A8.69 min

B5.00 min

C20.0 min

D40.0 min

Solution & Explanation:First-order integrated rate laws use natural logarithms: t = ln(0.800/0.200)/0.0693 = ln(4.00)/0.0693 = 20.0 min. Using log base 10 gives a value that is too small.

Problem 3Difficulty: Mastery

A balanced equation has 2A -> products. A student assumes the reaction must be second order and uses 1/[A]_t = 1/[A]_0 + kt. What is the main flaw?

AThe second-order integrated rate law never uses reciprocal concentration.

BReaction order must be determined from the rate law or data, not from the stoichiometric coefficient alone.

CAny reaction with coefficient 2 must be zero order.

DThe integrated rate law should use base-10 logarithms for all orders.

Solution & Explanation:Stoichiometric coefficients in the overall equation do not by themselves determine reaction order. Integrated rate laws should be chosen from experimental order or linearized data.

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Frequently Asked Questions

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QWhat grade level and standards does this worksheet align with?

This worksheet is designed specifically for Chemistry Science students. It aligns with educational standard NGSS HS-PS1-5; AP Chem Unit 5; CCSS HSS-ID and HSA-CED.A (National: NGSS HS-PS1-5; AP Chem Unit 5; CCSS HSS-ID and HSA-CED.A. State frameworks: TX TEKS reaction-rate expectations; FL SC.912.P.8.8 connections; CA/NY/NJ HS-PS1-5; MA chemistry reaction-rate standards; GA/VA kinetics standards.).