Free Printable WorksheetScienceGrade 8Science CurriculumSCI.8.40

8.40 Newton's Third Law and Collisions Worksheet

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Worksheet Overview & Skills Covered

Core academic competencies and curriculum alignment

This Grade 8 Science worksheet provides structured practice on 8.40 Newton's Third Law and Collisions. Students are guided through targeted exercises that build foundational understanding, computational accuracy, and critical thinking skills.

Newton’s Third Law and Collisions - Which description best equal‑and‑opposite force pairs during interactions and connect to safety features that reduce forces on occupants? (NGSS MS‑PS2‑1; SEP: Designing Solutions; TEKS §112.28 Grade 8; FL NGSSS; VA SOL; MA STE)

Whether you are an educator preparing classroom handouts, a tutor reinforcing weekly topics, or a parent supporting homeschool learning, this printable resource gives students the deliberate practice required to achieve subject fluency and master state standards.

Grade

Grade 8

Subject

Science

Domain

Science Curriculum

Formats

PDF & DOCX

Sample Practice Problems

Preview the types of problems and questions covered in this worksheet

Below are sample questions representative of the exercises included on this worksheet and related 8.40 Newton's Third Law and Collisions skill assessments:

Problem 1Difficulty: Mastery

Which statement best describes what must have changed?

AThe passenger’s momentum change became smaller even though they stopped.

BNewton’s third law stopped applying, so forces were reduced.

CThe passenger’s mass increased, reducing the impulse needed.

DThe stopping time increased so the same impulse could be delivered with a smaller peak/average force.

Solution & Explanation:Stopping still requires the same impulse (Δp) for the same initial speed and mass. To reduce peak force while keeping the area (impulse) the same, the interaction must last longer (greater Δt).

Problem 2Difficulty: Mastery

What is the speed and direction of the stuck-together pair?,A. About 7.1 m/s at 45° northeast | B. About 2.5 m/s due east | C. About 3.5 m/s at 45° northeast | D. 0 m/s because their momenta cancel,C,Total momentum is the vector sum: p_x = 0.20×5 = 1.0

Solution & Explanation:direction 45° (equal components).,NO,,,,,online_practice_skill_page,practice,grade 8 science newton's third law and collisions practice questions,newton's third law and collisions online practice | newton's third law and collisions review | SCI.8.40 practice | grade 8 science physical science: forces

Problem 3Difficulty: Mastery

What is the magnitude of the impulse on the 500 kg cart during the collision?

AAbout 6.67×10³ N·s

BAbout 3.33×10³ N·s

CAbout 1.67×10³ N·s

DAbout 1.00×10⁴ N·s

Solution & Explanation:Final speed v = (1000×10)/(1500) = 6.67 m/s. The 500 kg cart’s momentum change is Δp = 500(6.67−0) ≈ 3333 N·s, which equals the impulse magnitude on it.

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Frequently Asked Questions

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QWhat grade level and standards does this worksheet align with?

This worksheet is designed specifically for Grade 8 Science students. It aligns with educational standard SCI.8.40 (Identify action-reaction pairs and apply Newton's Third Law to collisions.).