Free Printable WorksheetScienceGrade 9Science CurriculumNGSS HS-PS3-3, HS-PS2-5

9.84 Ohm's Law and Circuit Calculations Worksheet

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Worksheet Overview & Skills Covered

Core academic competencies and curriculum alignment

This Physical Science with Earth and Science Science worksheet provides structured practice on 9.84 Ohm's Law and Circuit Calculations. Students are guided through targeted exercises that build foundational understanding, computational accuracy, and critical thinking skills.

Ohm's Law and Circuit Calculations: MCQ focus: solve simple V = IR relationships and compare current, voltage, and resistance from tables or circuit diagrams. Aligned to NGSS high school Physical Science, Earth and Space Science, and Engineering Design; NRC/DCI; SEP/CCC; CCSS math/literacy connections; selected CA NGSS, NYSSLS, Florida CPALMS, and Texas TEKS references NGSS HS-PS3-3, HS-PS2-5 - NGSS-aligned Ohm's Law and Circuit Calculations: NGSS: HS-PS3-3; HS-PS2-5; NRC/DCI: PS3.B; PS2.B; SEP/CCC: Using mathematics / Cause and effect; Common: HSN-Q.A; State refs: CA/NYSSLS same HS-PS PE family; FL SC.912.P.10; TX IPC energy strand.

Whether you are an educator preparing classroom handouts, a tutor reinforcing weekly topics, or a parent supporting homeschool learning, this printable resource gives students the deliberate practice required to achieve subject fluency and master state standards.

Grade

Physical Science with Earth and Science

Subject

Science

Domain

Science Curriculum

Formats

PDF & DOCX

Sample Practice Problems

Preview the types of problems and questions covered in this worksheet

Below are sample questions representative of the exercises included on this worksheet and related 9.84 Ohm's Law and Circuit Calculations skill assessments:

Problem 1Difficulty: Mastery

Use the circuit table: Trial 1 has 5 Ω and 2 A, Trial 2 has 10 Ω and 1 A, and Trial 3 has 20 Ω and 0.5 A. What is constant across the trials?

AVoltage is constant at 20 V.

BResistance is constant at 5 Ω.

CCurrent is constant at 2 A.

DVoltage is constant at 10 V.

Solution & Explanation:Calculate V = IR for each trial: 5 × 2 = 10 V, 10 × 1 = 10 V, and 20 × 0.5 = 10 V.

Problem 2Difficulty: Mastery

A voltage source is adjusted so the current through a 30 Ω resistor changes from 0.2 A to 0.5 A. By how much does the voltage increase?

A6 V

B9 V

C21 V

D15 V

Solution & Explanation:The voltage changes from 0.2 × 30 = 6 V to 0.5 × 30 = 15 V. The increase is 15 V - 6 V = 9 V.

Problem 3Difficulty: Mastery

Two components are tested one at a time. Component X has 6 V and 0.75 A. Component Y has 10 V and 1.25 A. Which comparison is true?

AComponent Y has greater resistance.

BThey have the same resistance.

CResistance cannot be compared from these measurements.

DComponent X has greater resistance.

Solution & Explanation:Component X has R = 6 ÷ 0.75 = 8 Ω. Component Y has R = 10 ÷ 1.25 = 8 Ω, so they are equal.

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Frequently Asked Questions

Common questions about printing, using, and solving this worksheet

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QWhat grade level and standards does this worksheet align with?

This worksheet is designed specifically for Physical Science with Earth and Science Science students. It aligns with educational standard NGSS HS-PS3-3, HS-PS2-5 (NGSS: HS-PS3-3; HS-PS2-5; NRC/DCI: PS3.B; PS2.B; SEP/CCC: Using mathematics / Cause and effect; Common: HSN-Q.A; State refs: CA/NYSSLS same HS-PS PE family; FL SC.912.P.10; TX IPC energy strand.).