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5.6 Multiply Multi Digit Whole Numbers Worksheet

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Worksheet Overview & Skills Covered

Core academic competencies and curriculum alignment

This Grade 5 Math worksheet provides structured practice on 5.6 Multiply Multi Digit Whole Numbers. Students are guided through targeted exercises that build foundational understanding, computational accuracy, and critical thinking skills.

Skill description: Select the correct value of multi-digit whole-number products (up to four-digit by two-digit) and identify a correct intermediate step or final product. Choose the statement that best justifies the answer using place-value language and an estimation check. Corresponding standards: CCSS 5.NBT.B.5.

Whether you are an educator preparing classroom handouts, a tutor reinforcing weekly topics, or a parent supporting homeschool learning, this printable resource gives students the deliberate practice required to achieve subject fluency and master state standards.

Grade

Grade 5

Subject

Math

Domain

Math Curriculum

Formats

PDF & DOCX

Sample Practice Problems

Preview the types of problems and questions covered in this worksheet

Below are sample questions representative of the exercises included on this worksheet and related 5.6 Multiply Multi Digit Whole Numbers skill assessments:

Problem 1Difficulty: Mastery

In 7,008 × 80, what is the tens-place partial product for multiplying by 80? (Write the number.)

Solution & Explanation:The tens digit in 80 stands for 80, not 8. So the tens-place partial product is 7,008 × 80 = 560,640. Estimation check: 7,008 ≈ 7,000 and 80 ≈ 80 (nearest ten), so the partial product is in the right size range.

Problem 2Difficulty: Mastery

A library orders the same number of bookmarks for each class. A student says 9,049 × 70 = 633,430. Which statement best justifies that answer using place value and an estimation check?

AEstimate 9,049 ≈ 9,000 and 70 ≈ 100, so the product is about 900,000; since this is close, 633,430 must be correct. (The estimate is not chosen carefully here.)

BBecause 70 = 7 + 0, compute 9,049 × 7 and 9,049 × 0; then add. This uses the digits of 70 without their place values.

CBecause 70 = 70 + 0, compute 9,049 × 70 = 633,430 and 9,049 × 0 = 0; then add to get 633,430. Estimation: 9,049 ≈ 9,000 and 70 ≈ 70, so the product is about 630,000, close to 633,430.

DMultiply by the tens digit to get 63,343 and by the ones digit to get 0; adding gives 63,343. This forgets that the tens digit represents tens.

Solution & Explanation:Break 70 into 70 + 0. 9,049 × 70 = 633,430 (because 70 is 7 tens). 9,049 × 0 = 0. Add the partial products: 633,430 + 0 = 633,430. Estimation check: 9,049 ≈ 9,000 and 70 ≈ 70, so 9,000 × 70 ≈ 630,000, which is close to 633,430.

Problem 3Difficulty: Mastery

A student says 6,907 × 72 = 497,304. Which statement best justifies that answer using place value and an estimation check?

ABecause 72 = 7 + 2, compute 6,907 × 7 and 6,907 × 2; then add. This uses the digits of 72 without their place values.

BMultiply by the tens digit to get 48,349 and by the ones digit to get 13,814; adding gives 62,163. This forgets that the tens digit represents tens.

CEstimate 6,907 ≈ 7,000 and 72 ≈ 100, so the product is about 700,000; since this is close, 497,304 must be correct. (The estimate is not chosen carefully here.)

DBecause 72 = 70 + 2, compute 6,907 × 70 = 483,490 and 6,907 × 2 = 13,814; then add to get 497,304. Estimation: 6,907 ≈ 6,900 and 72 ≈ 70, so the product is about 483,000, close to 497,304.

Solution & Explanation:Break 72 into 70 + 2. 6,907 × 70 = 483,490 (because 70 is 7 tens). 6,907 × 2 = 13,814. Add the partial products: 483,490 + 13,814 = 497,304. Estimation check: 6,907 ≈ 6,900 and 72 ≈ 70, so 6,900 × 70 ≈ 483,000, which is close to 497,304.

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