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7.16 Proportional equations from real world contexts Worksheet

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Worksheet Overview & Skills Covered

Core academic competencies and curriculum alignment

This Grade 7 Math worksheet provides structured practice on 7.16 Proportional equations from real world contexts. Students are guided through targeted exercises that build foundational understanding, computational accuracy, and critical thinking skills.

7.16 Proportional equations from real-world contexts - In multiple-choice items, students select the proportional equation that represents a context and the correct solution for an unknown quantity. (CCSS 7.RP.A.2c; CA 7.RP.2c; MA 7.RP.2c; NY 7.RP.2c; FL MA.7.AR.4.5; TX 7.4(A); VA 7.PFA.1)

Whether you are an educator preparing classroom handouts, a tutor reinforcing weekly topics, or a parent supporting homeschool learning, this printable resource gives students the deliberate practice required to achieve subject fluency and master state standards.

Grade

Grade 7

Subject

Math

Domain

Math Curriculum

Formats

PDF & DOCX

Sample Practice Problems

Preview the types of problems and questions covered in this worksheet

Below are sample questions representative of the exercises included on this worksheet and related 7.16 Proportional equations from real world contexts skill assessments:

Problem 1Difficulty: Mastery

In the emergency response drill, a dye blend uses 5.5 grams of dye for 200 milliliters of solution. You need 1.75 liters of the same blend. (Remember: 1 liter = 1000 milliliters.) Which proportional equation matches the situation, and what is x? (Let x be the number of grams of dye for 1750 milliliters.)

A200*x = 5.5 × 1750; x = 48.125

B1750*x = 5.5 × 200; x = 0.6286

C5.5*x = 200 × 1750; x = 63636.3636

D200 × 1750 = 5.5 + x; x = 349994.5

Solution & Explanation:Convert 1.75 liters to 1750 milliliters. Because the relationship is proportional, the ratio grams of dye:milliliters stays constant. Set up 200*x = 5.5 × 1750 where x is the amount of grams of dye for 1750 milliliters. Solve by dividing both sides by 200: x = (5.5 × 1750)/200 = 48.125.

Problem 2Difficulty: Mastery

At the refrigerated trucking depot, 4.2 meters of adhesive tape is used for 22 display boards. (Remember: 1 meter = 100 centimeters.) Which proportional equation matches the situation, and what is x? (Let x be the number of centimeters for 61 boards.)

A22 × 61 = 420 + x; x = 922

B420*x = 22 × 61; x = 3.1952

C22*x = 420 × 61; x = 1164.5455

D61*x = 420 × 22; x = 151.4754

Solution & Explanation:Convert 4.2 meters to 420 centimeters. Because the relationship is proportional, the ratio centimeters:boards stays constant. Set up 22*x = 420 × 61 where x is the amount of centimeters for 61 boards. Solve by dividing both sides by 22: x = (420 × 61)/22 = 1164.5455.

Problem 3Difficulty: Mastery

A log at the river cleanup crew shows a battery lasts 1.25 hours while running 12 identical test cycles. (Remember: 1 hour = 3600 seconds.) Which proportional equation matches the situation, and what is x? (Let x be the number of seconds for 30 test cycles.)

A4500*x = 12 × 30; x = 0.08

B12*x = 4500 × 30; x = 11250

C12 × 30 + x = 4500; x = 4140

D30*x = 4500 × 12; x = 1800

Solution & Explanation:Convert 1.25 hours to 4500 seconds. Because the relationship is proportional, the ratio seconds:test cycles stays constant. Set up 12*x = 4500 × 30 where x is the amount of seconds for 30 test cycles. Solve by dividing both sides by 12: x = (4500 × 30)/12 = 11250.

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QWhat grade level and standards does this worksheet align with?

This worksheet is designed specifically for Grade 7 Math students. It aligns with educational standard 7.16 (Practice and review Grade 7 math skill 7.16: Proportional Equations from Real-World Contexts.).