Free Printable WorksheetScienceGrade 12Science Curriculum12.113

12.113 Series Circuits Worksheet

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Worksheet Overview & Skills Covered

Core academic competencies and curriculum alignment

This Physics Science worksheet provides structured practice on 12.113 Series Circuits. Students are guided through targeted exercises that build foundational understanding, computational accuracy, and critical thinking skills.

Series Circuits: Determine equivalent resistance, current, voltage drops, and power distribution in series circuits. Aligned to NGSS, CCSS Literacy and Mathematics, AP Physics, and selected state frameworks 12.113 - Series Circuits: Corresponding standards/alignment: NGSS HS-PS2-4, HS-PS2-5, HS-PS3-2, HS-PS3-3, HS-PS3-5, HS-PS4-5; CCSS HSN-Q.A, HSA-CED.A, HSF-IF, HSG-MG; AP Physics 2 E&M units; AP Physics C: E&M enrichment; TX TEKS Physics §112.45(c) electricity and magnetism; FL SC.912.P.10, SC.912.P.12; VA PH.6; MA/CA/NY HS-PS2/HS-PS3/HS-PS4.

Whether you are an educator preparing classroom handouts, a tutor reinforcing weekly topics, or a parent supporting homeschool learning, this printable resource gives students the deliberate practice required to achieve subject fluency and master state standards.

Grade

Physics

Subject

Science

Domain

Science Curriculum

Formats

PDF & DOCX

Sample Practice Problems

Preview the types of problems and questions covered in this worksheet

Below are sample questions representative of the exercises included on this worksheet and related 12.113 Series Circuits skill assessments:

Problem 1Difficulty: Mastery

A 5 V drop is measured across a 10 Ω resistor in a series circuit. The whole circuit has a 30 V source. What is the equivalent resistance of the circuit?

A20 Ω

B30 Ω

C300 Ω

D60 Ω

Solution & Explanation:The current is I = 5 V/10 Ω = 0.5 A. The equivalent resistance for the whole circuit is R = 30 V/0.5 A = 60 Ω.

Problem 2Difficulty: Mastery

A 24 V battery is connected to R1 = 2 Ω, R2 = 4 Ω, and R3 = 6 Ω in series. If R3 is replaced with 18 Ω, what happens to the power in R1?

AIt increases from 8 W to 18 W.

BIt stays at 8 W.

CIt decreases from 8 W to 2 W.

DIt decreases from 4 W to 2 W.

Solution & Explanation:Initially Rtotal = 12 Ω and I = 2 A, so P1 = I^2R1 = 8 W. After replacement Rtotal = 24 Ω and I = 1 A, so P1 = 2 W.

Problem 3Difficulty: Mastery

A 120 V source powers a 30 Ω resistor and a 70 Ω resistor in series. A device can tolerate at most 75 W and must be placed where power is lower. Which resistor location is safer for the device model?

AUse the 70 Ω location, where power is 100.8 W.

BUse the 30 Ω location, where power is 43.2 W.

CEither location, because both powers are 75 W.

DNeither location, because both powers are zero.

Solution & Explanation:The current is 120 V/(30 Ω + 70 Ω) = 1.2 A. Powers are I^2R: 43.2 W in 30 Ω and 100.8 W in 70 Ω, so only the 30 Ω location is below 75 W.

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Frequently Asked Questions

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QWhat grade level and standards does this worksheet align with?

This worksheet is designed specifically for Physics Science students. It aligns with educational standard 12.113 (Corresponding standards/alignment: NGSS HS-PS2-4, HS-PS2-5, HS-PS3-2, HS-PS3-3, HS-PS3-5, HS-PS4-5; CCSS HSN-Q.A, HSA-CED.A, HSF-IF, HSG-MG; AP Physics 2 E&M units; AP Physics C: E&M enrichment; TX TEKS Physics §112.45(c) electricity and magnetism; FL SC.912.P.10, SC.912.P.12; VA PH.6; MA/CA/NY HS-PS2/HS-PS3/HS-PS4.).