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12.26 Constant Acceleration Equations Worksheet

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Worksheet Overview & Skills Covered

Core academic competencies and curriculum alignment

This Physics Science worksheet provides structured practice on 12.26 Constant Acceleration Equations. Students are guided through targeted exercises that build foundational understanding, computational accuracy, and critical thinking skills.

Constant-Acceleration Equations: Select the correct kinematic equation, variable substitution, or unknown value for constant-acceleration motion. Aligned to NGSS, CCSS Literacy and Mathematics, AP Physics, and selected state frameworks 12.26 - Constant-Acceleration Equations: NGSS HS-PS2-1 and SEPs; CCSS HSN-Q.A, HSA-CED.A, HSF-IF, HSF-BF, HSS-ID; AP Physics 1 Unit 1; AP Physics C: Mechanics kinematics enrichment; TX TEKS Physics §112.45(c) motion; FL SC.912.P.12.2; VA PH.2; MA/CA/NY HS-PS2.

Whether you are an educator preparing classroom handouts, a tutor reinforcing weekly topics, or a parent supporting homeschool learning, this printable resource gives students the deliberate practice required to achieve subject fluency and master state standards.

Grade

Physics

Subject

Science

Domain

Science Curriculum

Formats

PDF & DOCX

Sample Practice Problems

Preview the types of problems and questions covered in this worksheet

Below are sample questions representative of the exercises included on this worksheet and related 12.26 Constant Acceleration Equations skill assessments:

Problem 1Difficulty: Mastery

A cart is at x = +10 m with v0 = +6 m/s and a = -2.0 m/s². After 5.0 s, which position and velocity pair is correct?

Ax = +40 m and v = -4 m/s

Bx = +15 m and v = -4 m/s

Cx = +15 m and v = +4 m/s

Dx = -15 m and v = -4 m/s

Solution & Explanation:Use v = 6 + (-2.0)(5.0) = -4 m/s. Position is x = 10 + 6(5.0) + (1/2)(-2.0)(5.0)² = 10 + 30 - 25 = 15 m.

Problem 2Difficulty: Mastery

Which equation is dimensionally valid for constant-acceleration position in one dimension?

Ax = x0 + v0 + at

Bx = x0 + v0t + (1/2)at²

Cx = x0t + v0t + (1/2)a

Dx = x0 + v0t² + at

Solution & Explanation:Each term in a position equation must have units of meters. x0, v0t, and (1/2)at² are all lengths, so x = x0 + v0t + (1/2)at² is dimensionally valid.

Problem 3Difficulty: Mastery

Use the sensor table in the image. Assuming constant acceleration, what displacement occurs from t = 2 s to t = 5 s?

A+33.0 m

B+42.0 m

C+46.5 m

D+60.0 m

Solution & Explanation:The endpoint velocities are +11 m/s and +20 m/s. The average velocity is 15.5 m/s over 3 s, so displacement is 15.5(3) = 46.5 m.

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Frequently Asked Questions

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QWhat grade level and standards does this worksheet align with?

This worksheet is designed specifically for Physics Science students. It aligns with educational standard 12.26 (NGSS HS-PS2-1 and SEPs; CCSS HSN-Q.A, HSA-CED.A, HSF-IF, HSF-BF, HSS-ID; AP Physics 1 Unit 1; AP Physics C: Mechanics kinematics enrichment; TX TEKS Physics §112.45(c) motion; FL SC.912.P.12.2; VA PH.2; MA/CA/NY HS-PS2.).