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12.28 Projectile Motion in Two Dimensions Worksheet

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Worksheet Overview & Skills Covered

Core academic competencies and curriculum alignment

This Physics Science worksheet provides structured practice on 12.28 Projectile Motion in Two Dimensions. Students are guided through targeted exercises that build foundational understanding, computational accuracy, and critical thinking skills.

Projectile Motion in Two Dimensions: Choose the correct horizontal and vertical motion reasoning for projectiles launched horizontally or at an angle. Aligned to NGSS, CCSS Literacy and Mathematics, AP Physics, and selected state frameworks 12.28 - Projectile Motion in Two Dimensions: NGSS HS-PS2-1 and SEPs; CCSS HSN-Q.A, HSA-CED.A, HSF-IF, HSF-BF, HSS-ID; AP Physics 1 Unit 1; AP Physics C: Mechanics kinematics enrichment; TX TEKS Physics §112.45(c) motion; FL SC.912.P.12.2; VA PH.2; MA/CA/NY HS-PS2.

Whether you are an educator preparing classroom handouts, a tutor reinforcing weekly topics, or a parent supporting homeschool learning, this printable resource gives students the deliberate practice required to achieve subject fluency and master state standards.

Grade

Physics

Subject

Science

Domain

Science Curriculum

Formats

PDF & DOCX

Sample Practice Problems

Preview the types of problems and questions covered in this worksheet

Below are sample questions representative of the exercises included on this worksheet and related 12.28 Projectile Motion in Two Dimensions skill assessments:

Problem 1Difficulty: Mastery

An angled projectile reaches its maximum height 2.0 s after launch while its horizontal velocity is 18 m/s. Use g = 9.8 m/s². Which statement correctly links the horizontal and vertical motions at the top?

AIts initial vertical velocity was 9.8 m/s, and it has moved 18 m horizontally by the top.

BIts initial vertical velocity was 19.6 m/s, and its horizontal displacement at the top is 0 m.

CIts vertical velocity is 19.6 m/s at the top, and its horizontal velocity is 0 m/s there.

DIts initial vertical velocity was 19.6 m/s, and it has moved 36 m horizontally by the top.

Solution & Explanation:The top occurs when v_y = 0, so v_y0 = gt = 9.8(2.0) = 19.6 m/s. Horizontal motion continues at 18 m/s for the same 2.0 s, giving x = 36 m.

Problem 2Difficulty: Mastery

Which reasoning statement best summarizes ideal projectile motion in two dimensions?

AHorizontal and vertical motions are independent because they occur during different time intervals.

BThe projectile's acceleration follows the curve while its speed remains constant.

CHorizontal motion is constant-velocity motion, vertical motion is constant-acceleration motion, and the same time variable connects them.

DVertical motion is constant velocity, while horizontal motion is accelerated by gravity.

Solution & Explanation:The dimensions can be analyzed separately, but they share the same time. With no air resistance, horizontal acceleration is zero and vertical acceleration is the constant downward value g.

Problem 3Difficulty: Mastery

A measured v_x(t) graph for a projectile slopes downward instead of staying horizontal. Which assumption of the ideal projectile model is most directly violated?

AThe vertical acceleration is downward.

BNo horizontal force or air resistance acts on the projectile.

CThe projectile has a vertical velocity component.

DThe projectile is moving in two dimensions.

Solution & Explanation:A decreasing horizontal velocity implies horizontal acceleration. In the ideal model, no air resistance or horizontal force acts, so v_x should be constant.

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QWhat grade level and standards does this worksheet align with?

This worksheet is designed specifically for Physics Science students. It aligns with educational standard 12.28 (NGSS HS-PS2-1 and SEPs; CCSS HSN-Q.A, HSA-CED.A, HSF-IF, HSF-BF, HSS-ID; AP Physics 1 Unit 1; AP Physics C: Mechanics kinematics enrichment; TX TEKS Physics §112.45(c) motion; FL SC.912.P.12.2; VA PH.2; MA/CA/NY HS-PS2.).