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Solve Linear Systems by Substitution
Grade Level
Praxis Core
5165.057 Solve Linear Systems by Substitution
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Use substitution to solve the system x + (2/3)y = 40/3; 2x – 5y = -43. Which option is correct?
A
Rewrite the first equation as x = -(2/3)y + 40/3. Substitute -(2/3)y + 40/3 for x in 2x - 5y = -43 to get 2(-(2/3)y + 40/3) - 5y = -43; y = 11, then x = 6; solution (6, 11).
B
Rewrite the first equation as x = -(2/3)y - 40/3. Substitute -(2/3)y - 40/3 for x in 2x - 5y = -43; y = 49/19, then x = -286/19; solution (-286/19, 49/19).
C
Use the substitution x = -(2/3)y + 40/3 in 2x - 5y = -43; the values are reversed as x = 11 and y = 6, so the solution is (11, 6).
D
Substitute -(2/3)y + 40/3 for x in 2x - 5y = -43 to get 2(-(2/3)y + 40/3) - 5y = -43; y = 12, then x = 16/3; solution (16/3, 12).
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